Question

Construct a ΔABC with AB = 6 cm, BC = 5 cm and ∠B = 60°. Now construct another triangle whose sides are `2/3` times the corresponding sides of ΔABC.

Answer 1

Steps of construction:

1. Draw a line segment BC = 5 cm.
2. At point B, draw a line by making an angle of 60°.
3. With B as centre mark an arc A of length 6 cm.
4. Join CA.
5. Draw a ray BX making an acute angle with BC.
6. Locate three points B₁, B₂, B₃ on the line segment BX at equal distance.
7. Join B₃ C. Draw a parallel line through B₂ to B₃ C intersecting line segment BC at C'.
8. Through C' draw a line parallel to AC intersecting line segment AB at A. Hence, ΔA' BC' is the required triangle.