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प्रश्न
Concentrated sulphuric acid is both an oxidizing agent and a non-volatile acid. Write one equation each to illustrate the properties of sulphuric acid mentioned above.
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उत्तर
As an Oxidizing agent :
H2SO4 → H2O + SO2 + [O]
C + 2[O] → CO2
As a non-volatile acid :
\[\ce{NaCl + H2SO4 ->[200°C] NaHSO4 + HCl}\]
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संबंधित प्रश्न
Give two balanced reactions of the type to show the following property of sulphuric acid:
Acidic nature
What would you observe in the following case?
Hot concentrated sulphuric acid is added to sodium chloride crystals.
Give reason for the following:
When concentrated sulphuric acid is added to blue crystalline copper sulphate, it turns powdery white.
Describe the reaction that show
Dilute sulphuric acid behaves as dibasic acid.
Give reason for the following:
Concentrated sulphuric acid is kept in airtight bottles.
- Name the catalyst which helps in the conversion of sulphur dioxide to sulphur trioxide in step C.
- In the contact process for the manufacture of sulphuric acid, sulphur trioxide is not converted to sulphuric acid by reacting it with water. Instead a two-step procedure is used. Write the equations for the two steps involved in D.
- What type of substance will liberate sulphur dioxide from sodium sulphite in step E?
- Write the equation for the reaction by which sulphur dioxide is converted to sodium sulphite in step F.
Write balanced equation for potassium hydrogen carbonate and dilute sulphuric acid.
Write the equation of the following reaction:
Sulphur is heated with concentrated sulphuric acid.
State your observation for the following case :
Moist blue litmus is introduced into a gas jar of sulphur dioxide.
Write a balanced equation for the following conversion:
Lead sulphate from lead nitrate and sulphuric acid.
