Advertisements
Advertisements
प्रश्न
Compute the amount and the compound interest in the following by using the formulae when:
Principal = Rs 160000, Rate = 10 paise per rupee per annum compounded half-yearly, Time = 2 years.
Advertisements
उत्तर
\[\text{ Applying the rule A = P }\left( 1 + \frac{R}{100} \right)^n \text{ on the given situations, we get: }\]
\[A = 16, 000 \left( 1 + \frac{10}{200} \right)^4 \]
\[ = 16, 000 \left( 1 . 05 \right)^4 \]
= Rs 19, 448 . 1
Now,
CI = A - P
= Rs 19, 448 . 1 - Rs 16, 000
= Rs 3, 448 . 1
संबंधित प्रश्न
The population of a place increased to 54,000 in 2003 at a rate of 5% per annum. what would be its population in 2005?
Compute the amount and the compound interest in the following by using the formulae when:
Principal = Rs 12800, Rate = \[7\frac{1}{2} %\], Time = 3 years
Compute the amount and the compound interest in the following by using the formulae when:
Principal = Rs 10000, Rate 20% per annum compounded half-yearly, Time = 2 years
At what rate percent will a sum of Rs 1000 amount to Rs 1102.50 in 2 years at compound interest?
The compound interest on Rs 1800 at 10% per annum for a certain period of time is Rs 378. Find the time in years.
The population of a city is 125000. If the annual birth rate and death rate are 5.5% and 3.5% respectively, calculate the population of city after 3 years.
Ashish started the business with an initial investment of Rs 500000. In the first year he incurred a loss of 4%. However during the second year he earned a profit of 5% which in third year rose to 10%. Calculate the net profit for the entire period of 3 years.
The cost price of a machine is 2,50,000. If the rate of depreciation is 10% per year, find the depreciation in price of the machine after two years.
A principal amounts to ₹ 13,924 in 2 years by compound interest at 18 p.c.p.a. Find the principal.
The population of a suburb is 16000. Find the rate of increase in the population if the population after two years is 17640.
