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प्रश्न
Complete the following activity to find the value of discriminant of the equation x2 + 10x − 7 = 0.
Solution:
Comparing x2 + 10x − 7 = 0 with ax2 + bx + c = 0
a = 1, b = 10, c = `square`
∴ b2 − 4ac = `square` − 4 × 1 × (−7)
= 100 + `square`
= `square`
योग
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उत्तर
Comparing x2 + 10x − 7 = 0 with ax2 + bx + c = 0
a = 1, b = 10, c = \[\boxed{-7}\]
∴ b2 − 4ac = \[\boxed{10^2}\] − 4 × 1 × (−7)
= 100 + \[\boxed{28}\]
= \[\boxed{128}\]
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