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प्रश्न
Complete the activity to find the value of x.
3x + 2y = 11 ...(i) and 2x + 3y = 4 ...(ii)
Solution:
Multiply equation (i) by ______ and equation (ii) by ______.
`square` × (3x + 2y = 11) ∴ 9x + 6y = 33 ...(iii)
`square` × (2x + 3y = 4) ∴ 4x + 6y = 8 ...(iv)
Subtract (iv) from (iii),
`square` x = 25
∴ x = `square`
कृति
योग
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उत्तर
3x + 2y = 11 ...(i) and 2x + 3y = 4 ...(ii)
Multiply equation (i) by \[\boxed{3}\] and equation (ii) by \[\boxed{2}\].
\[\boxed{3}\] × (3x + 2y = 11) ∴ 9x + 6y = 33 ...(iii)
\[\boxed{2}\] × (2x + 3y = 4) ∴ 4x + 6y = 8 ...(iv)
Subtract (iv) from (iii),
\[\boxed{5}\]x = 25
∴ x = `25/5`
∴ x = \[\boxed{5}\]
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