Question

Complete and state whether the reaction is oxidation or reduction.

\[\ce{Pb^{2+} +}\] .......... \[\ce{-> Pb}\]

Answer 1

\[\ce{Pb^{2+} + 2e- -> Pb}\]

The lead ion gains 2 electrons to cancel out its positive charge, becoming neutral lead metal. Since gaining an electron is a reduction reaction, hence this reaction is a reduction reaction.