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Compare the Modal Ages of Two Groups of Students Appearing for an Entrance Test: - Mathematics

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प्रश्न

Compare the modal ages of two groups of students appearing for an entrance test:

Age (in years): 16-18 18-20 20-22 22-24 24-26
Group A: 50 78 46 28 23
Group B: 54 89 40 25 17
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उत्तर

Age (in years) Group ‘A’ Group ‘B’
16–18  50 54
18–20  78 89
20–22  46 40
22–24 28 25
24–25 23 17

For group “A”

The maximum frequency is 78 so the modal class is 18–20.

Therefore,

l = 18

h = 2

f = 78

f1 = 50

f2 = 46

Mode `rArr=l+(f-f1)/(2f-f1-f2)xxh`

`=18+(78-50)/(156-50-46)xx2`

`=18+28/60xx2`

`=18+14/15`

= 18 + 0.93

= 18.93

For group “B”

The maximum frequency 89 so modal class 18–20.

Therefore,

l = 18

h = 2

f = 89

f1 = 54

f2 = 40

Mode `rArr=l+(f-f1)/(2f-f1-f2)xxh`

`=18+(89-54)/(178-54-40)xx2`

`=18+35/84xx2`

`=18+35/42`

`=18+5/6`

= 18 + 0.83

= 18.83

Thus, the modal age of group A is 18.93 years whereas the modal age of group B is 18.83 years.

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अध्याय 15: Statistics - Exercise 15.5 [पृष्ठ ४५]

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आरडी शर्मा Mathematics [English] Class 10
अध्याय 15 Statistics
Exercise 15.5 | Q 4 | पृष्ठ ४५
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