Advertisements
Advertisements
प्रश्न
Common factor of 11pq2, 121p2q3, 1331p2q is 11p2q2.
विकल्प
True
False
Advertisements
उत्तर
This statement is False.
Explanation:
We have,
11pq2 = 11 × p × q × q
121p2q3 = 11 × 11 × p × p × q × q × q
1331p2q = 11 × 11 × 11 × p × p × q
∴ Common factor = 11 × p × q = 11pq
APPEARS IN
संबंधित प्रश्न
For the following monomials, write its degree: 7y
Add : 2x + y and 3x – 4y
Find the sum of:
9ax – 6bx + 8, 4ax + 8bx – 7 and – 6ax – 4bx – 3
Enclose the given term in bracket as required:
x2 -y2 + z2 + 3x – 2y = x2 – (……..)
Simplify: 5 − 8x − 6 − x
Find the missing term
_________ × (−15m2n3p) = 45m3n3p2
Factorise the following expression.
24x2yz3 – 6xy3z2 + 15x2y2z – 5xyz
Factorise the following expression.
lx + my + mx + ly
Identify term and factor in the expression given below:
xy + 2x2y2
In like terms, the numerical coefficients should also be the same.
