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प्रश्न
Choose the correct statement.
विकल्प
Square planar complexes are more stable than octahedral complexes
The spin only magnetic moment of \[\ce{[Cu(Cl)4]^2-}\] is 1.732 BM and it has square planar structure.
Crystal field splitting energy (Δ0) of \[\ce{[FeF6]^4-}\] is higher than the (Δ0) of \[\ce{[Fe(CN)6]^4-}\]
Crystal field stabilization energy of \[\ce{[V(H2O)6]^2+}\] is higher than the crystal field stabilization of \[\ce{[Ti(H2O)6]^2+}\]
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उत्तर
Crystal field stabilization energy of \[\ce{[V(H2O)6]^2+}\] is higher than the crystal field stabilization of \[\ce{[Ti(H2O)6]^2+}\]
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संबंधित प्रश्न
As per IUPAC guidelines, the name of the complex [Co(en)2(ONO)Cl]Cl is
Crystal field stabilization energy for high spin d5 octahedral complex is ____________.
Arrange the following in order of increasing molar conductivity.
i) \[\ce{Mg[Cr(NH3) (Cl)5]}\]
ii) \[\ce{[Cr(NH3)5 Cl]3 [CoF6]2}\]
iii) \[\ce{[Cr(NH3)3 Cl3]}\]
Give an example for a complex of the type [Ma2b2c2] where a, b, c are monodentate ligands and give the possible isomers.
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In an octahedral crystal field, draw the figure to show the splitting of d orbitals.
Why tetrahedral complexes do not exhibit geometrical isomerism.
What is crystal field stabilization energy (CFSE)?
What are the limitations of VB theory?
Write the oxidation state, coordination number, nature of ligand, magnetic property and electronic configuration in octahedral crystal field for the complex \[\ce{K4[Mn(CN)6]}\].
