Advertisements
Advertisements
प्रश्न
Choose the correct statement.
विकल्प
Square planar complexes are more stable than octahedral complexes
The spin only magnetic moment of \[\ce{[Cu(Cl)4]^2-}\] is 1.732 BM and it has square planar structure.
Crystal field splitting energy (Δ0) of \[\ce{[FeF6]^4-}\] is higher than the (Δ0) of \[\ce{[Fe(CN)6]^4-}\]
Crystal field stabilization energy of \[\ce{[V(H2O)6]^2+}\] is higher than the crystal field stabilization of \[\ce{[Ti(H2O)6]^2+}\]
Advertisements
उत्तर
Crystal field stabilization energy of \[\ce{[V(H2O)6]^2+}\] is higher than the crystal field stabilization of \[\ce{[Ti(H2O)6]^2+}\]
APPEARS IN
संबंधित प्रश्न
The sum of primary valence and secondary valence of the metal M in the complex [M(en)2(Ox)]Cl is ____________.
As per IUPAC guidelines, the name of the complex [Co(en)2(ONO)Cl]Cl is
Crystal field stabilization energy for high spin d5 octahedral complex is ____________.
Arrange the following in order of increasing molar conductivity.
i) \[\ce{Mg[Cr(NH3) (Cl)5]}\]
ii) \[\ce{[Cr(NH3)5 Cl]3 [CoF6]2}\]
iii) \[\ce{[Cr(NH3)3 Cl3]}\]
Give one test to differentiate \[\ce{[Co(NH3)5Cl]SO4}\] and \[\ce{[Co(NH3)5SO4]Cl}\].
In an octahedral crystal field, draw the figure to show the splitting of d orbitals.
Why tetrahedral complexes do not exhibit geometrical isomerism.
What is crystal field stabilization energy (CFSE)?
Discuss briefly the nature of bonding in metal carbonyls.
Write the oxidation state, coordination number, nature of ligand, magnetic property and electronic configuration in octahedral crystal field for the complex \[\ce{K4[Mn(CN)6]}\].
