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Choose the correct alternative: The equation of a circle with origin as centre and passing through the vertices of an equilateral triangle whose median is of length 3a is

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प्रश्न

Choose the correct alternative:

The equation of a circle with origin as centre and passing through the vertices of an equilateral triangle whose median is of length 3a is

विकल्प

  • x2 + y2 = 9a2 

  • x2 + y2 = 16a2 

  • x2 + y2 = 4a2 

  • x2 + y2 = a2 

MCQ
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उत्तर

x2 + y2 = 4a2 

Explanation;

Since the triangle is equilateral.

∴ The centroid of the triangle is same as the circumcentre;

and radius of the circumcircle = `2/3("median")`

= `2/3(3"a")`

= 2a

Hence, the equation of the circumcircle whose centre is at (0, 0) and radius 2a is x2 + y2 = 4a2.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Circle - Miscellaneous Exercise 6 [पृष्ठ १३७]

APPEARS IN

बालभारती Mathematics and Statistics (Arts and Science) Part 1 [English] Standard 11 Maharashtra State Board
अध्याय 6 Circle
Miscellaneous Exercise 6 | Q I. (8) | पृष्ठ १३७

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