हिंदी

Choose the Correct Alternative Answer for the Following Question. Cosec 45° = ?

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प्रश्न

Choose the correct alternative answer for the following question.
cosec 45° =?

विकल्प

  • \[\frac{1}{2}\]

  • \[\sqrt{2}\] 

  • \[\frac{\sqrt{3}}{2}\] 

  • \[\frac{2}{\sqrt{3}}\] 

MCQ
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उत्तर

\[cosec45^\circ = \sqrt{2}\]

Hence, the correct answer is \[\sqrt{2}\] .

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Trigonometry - Problem Set 6 [पृष्ठ १३८]

APPEARS IN

बालभारती Geometry Mathematics 2 [English] Standard 10 Maharashtra State Board
अध्याय 6 Trigonometry
Problem Set 6 | Q 1.2 | पृष्ठ १३८

संबंधित प्रश्न

If \[\cot\theta = \frac{40}{9}\], find the values of cosecθ and sinθ.


If 5 secθ – 12 cosecθ = 0, find the values of secθ, cosθ, and sinθ.


If tanθ = 1 then, find the value of

`(sinθ + cosθ)/(secθ + cosecθ)`


Prove that:

cos2θ (1 + tan2θ)


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\[\sqrt{\frac{1 - \sin\theta}{1 + \sin\theta}} = \sec\theta - \tan\theta\]

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(secθ - cosθ)(cotθ + tanθ) = tanθ.secθ.


Prove that:

\[\cot\theta + \tan\theta = cosec\theta \sec\theta\]

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\[\sec\theta + \tan\theta = \frac{\cos\theta}{1 - \sin\theta}\]

Choose the correct alternative answer for the following question.

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Choose the correct alternative answer for the following question.

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\[\frac{\tan^3 \theta - 1}{\tan\theta - 1} = \sec^2 \theta + \tan\theta\]

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Prove that: (sec θ – cos θ) (cot θ + tan θ) = tan θ.sec θ

Proof: L.H.S. = (sec θ – cos θ) (cot θ + tan θ)

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= `((1 - square)/square) ((square + square)/(square  square))`

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= tan θ.sec θ

= R.H.S.

∴ L.H.S. = R.H.S.

∴ (sec θ – cos θ) (cot θ + tan θ) = tan θ.sec θ


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