Question

Check the ordered points (1, −1), (2, −1) is a solution of 2x + 3y − 6 ≤ 0

Answer 1

Given inequality: 2x + 3y – 6 ≤ 0

i.e., 2x + 3y ≤ 6       .......(i)

Consider point (1, –1).

Putting x = 1 and y = –1 in equation (i), we get

2(1) + 3(–1) = 2 – 3

= – 1 ≤ 6

which is true.

Consider point (2, –1)

Putting x = 2 and y = –1 in equation (i), we get

2(2) + 3(–1) = 4 – 3

= 1 ≤ 6

which is true.

∴ Given ordered pairs are solutions of 2x + 3y – 6 ≤ 0.