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प्रश्न
Carry out the following divisions:
−36y3 ÷ 9y2
योग
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उत्तर
−36y3 = −1 × 2 × 2 × 3 × 3 × y × y × y
9y2 = 3 × 3 × y × y
−36y3 ÷ 9y2
= `(-1 xx 2 xx 2 xx 3 xx 3 xx y xx y xx y)/(3 xx 3 xx y xx y)`
= −2 × 2 × y
= −4y
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अध्याय 12: Factorisation - EXERCISE 12.3 [पृष्ठ १५५]
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संबंधित प्रश्न
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Divide (3xy)2 by 9xy
Simplify `(3"m"^2)/"m" + (2"m"^4)/("m"^3)`
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Statement A: 4x2 + 3x – 2 = `2(2x^2 + (3x)/2 - 1)`
Statement B: (2m – 5) – (5 – 2m) = (2m – 5) + (2m – 5)
