हिंदी

Calculate the work done in blowing a soap bubble to a radius of 1 cm. The surface tension of soap solution is 2.5 × 10−2 N/m.

Advertisements
Advertisements

प्रश्न

Calculate the work done in blowing a soap bubble to a radius of 1 cm. The surface tension of soap solution is 2.5 × 10−2 N/m.

संख्यात्मक
Advertisements

उत्तर

Given:

T = 2.5 × 102 N/m, r1 = 0 m, r2 = 1 cm = 102 m, W = ?

Formula:

W = T dA 

= T (2 × 4π r2 − 0)

= T × 8 π r2

= 2.5 × 102 × 8 × π × (102)2

= 2.5 × 8 × 3.14 × (102)

= 6.275 × 105 J

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2022-2023 (March) Official

संबंधित प्रश्न

Derive the relation between surface tension and surface energy per unit area.


The radius of a soap bubble is blown up to double its value under isothermal conditions. If 'r' be the initial radius of the bubble, and T be the surface tension, then energy spent in doubling the radius is ______


Which one of the following statements is correct?


A liquid drop having surface energy 'E' is spread into 216 droplets of same size. The final surface energy of the droplets is ____________.


The surface energy of a liquid drop is u. If it is sprayed into 1000 equal droplets, then its surface energy becomes ______.


If a million tiny droplets of water of the same radius coalesce into one larger drop, then the ratio of the surface energy of the large drop to the total surface energy of all the droplets will be ____________.


On the surface of the liquid in equilibrium, molecules of the liquid possess ____________.


Consider a process shown in the figure. During this process, the work done by the system ______.


A metal coin of thickness 'd' and density 'ρ' is floating on water of surface tension 'T'. The radius of the coin is ______.

g = acceleration due to gravity


One thousand small water drops of equal radii combine to form a big drop. The ratio of final surface energy to the total initial surface energy is ______.


One cubic plate, having a 15 cm side, floats on water surface. If surface tension of water is 60 dyne/cm. To lift this plate from water, Find the extra force required against weight.


If T1, T2 and T3 are the forces due to surface tension at the liquid-s solid-gas and liquid-gas interfaces such that T2 - T1 ≅ T3 and the contact angle for the liquid-solid pair is θ then ______.


Prove that, equivalent S.I. unit of surface tension is J/m2.


Calculate the amount of energy evolved when 343 droplets of mercury each of radius. 0.05 mm, combine to form one drop. The surface tension of mercury is 50 x 10-2 N/m.


A liquid drop having surface energy E is spread into 729 droplets of same size. The final surface aenergy of the droplets is ______.


A water drop of 0.01 cm³ is squeezed between two glass plates and spreads in to area of 10 cm². If surface tension of water is 70 dyne / cm then the normal force required to separate glass plates from each other will be ______.


A big drop is formed by coalescing 1000 small droplets of water. The surface energy will become ______.


Work done to get ‘n’ spherical drops of equal size from a single spherical drop of water, is proportional to ______.


A rectangular film of liquid is extended from 2 cm × 3.5 cm to 2 cm × 4.5 cm. If the work done is 6.4 × 10−5 J, the surface tension of the liquid is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×