हिंदी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान कक्षा ११

Calculate the oxidation number of phosphorus in the following species. HPOX32− - Chemistry

Advertisements
Advertisements

प्रश्न

Calculate the oxidation number of phosphorus in the following species.

\[\ce{HPO^{2-}3}\]

टिप्पणी लिखिए
Advertisements

उत्तर

Let the oxidation number of P in \[\ce{HPO^{2-}3}\] be x.

Therefore, +1 + x + (– 6) = – 2 

x = +3

Oxidation number of phosphorus is +3.

shaalaa.com
Oxidation Number - Introduction
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Redox Reactions - Multiple Choice Questions (Type - I) [पृष्ठ १०८]

APPEARS IN

एनसीईआरटी एक्झांप्लर Chemistry [English] Class 11
अध्याय 8 Redox Reactions
Multiple Choice Questions (Type - I) | Q 22.(a) | पृष्ठ १०८

संबंधित प्रश्न

Assign oxidation numbers to the underlined element in the following species:

 NaH2PO4


Assign oxidation numbers to the underlined element in the following species:

H4P2O7


Assign oxidation numbers to the underlined elements in the following species:

H2S2O7


Assign oxidation numbers to the underlined elements in the following species:

KAl(SO4)2.12 H2O


What are the oxidation numbers of the underlined elements in the following and how do you rationalise your results?

KI3


What are the oxidation numbers of the underlined elements in the following and how do you rationalise your results?

CH3CH2OH


What is the oxidation number of the underlined elements in the following and how do you rationalise your results?

CH3COOH


Consider the elements: Cs, Ne, I and F

Identify the element that exhibits only negative oxidation state.


Consider the elements : Cs, Ne, I and F

Identify the element which exhibits neither the negative nor does the positive oxidation state.


The exhibition of various oxidation states by an element is also related to the outer orbital electronic configuration of its atom. Atom(s) having which of the following outermost electronic configurations will exhibit more than one oxidation state in its compounds.

(i) 3s1

(ii) 3d14s2

(iii) 3d24s2

(iv) 3s23p3 


\[\ce{PbO}\] and \[\ce{PbO2}\] react with \[\ce{HCl}] according to following chemical equations:

\[\ce{2PbO + 4HCl -> 2PbCl2 + 2H2O}\]

\[\ce{PbO2 + 4HCl -> PbCl2 + Cl2 + 2H2O}\]

Why do these compounds differ in their reactivity?


Calculate the oxidation number of sulphur atom in the following compounds:

\[\ce{Na2S2O3}\]


Calculate the oxidation number of sulphur atom in the following compounds:

\[\ce{Na2S4O6}\]


Match Column I with Column II for the oxidation states of the central atoms.

  Column I Column II
(i) Ions having positive charge (a) +7
(ii) The sum of oxidation number
of all atoms in a neutral molecule
(b) –1
(iii) Oxidation number of hydrogen ion \[\ce{(H+)}\] (c) +1
(iv) Oxidation number of fluorine in \[\ce{NaF}\] (d) 0
(v) Ions having negative charge (e) Cation
    (f) Anion

The oxidation number of U in \[\ce{UO2(NO3)2}\] is ______. 


The oxidation number and covalency of sulphur in sulphur molecules (Sg) are:


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×