Advertisements
Advertisements
प्रश्न
Calculate the osmotic pressure in pascals exerted by a solution prepared by dissolving 1.0 g of polymer of molar mass 185,000 in 450 mL of water at 37°C.
Advertisements
उत्तर
Given: Number of moles of solute dissolved (n) = `(1.0 g)/(185000 g "mol"^(-1)) = 1/(185000)` mol
V = 450 mL = 0.45 L
T = 37°C = (37 + 273) K = 310 K
R = 8.314 k Pa L K−1 mol−1 = 8.314 × 103 Pa L K−1 mol−1
Osmotic pressure (π) = `n/V RT`
= `1/(185000) "mol" xx 1/(0.45 L) xx 8.314 xx 10^3 Pa L K^(-1) "mol"^(-1) xx 310 K`
= 30.96 Pa
= 31 Pa (approximately)
APPEARS IN
संबंधित प्रश्न
Which of the following is not a colligative property?
At 300 K, 36 g of glucose present in a litre of its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of the solution is 1.52 bars at the same temperature, what would be its concentration?
Determine the amount of CaCl2 (i = 2.47) dissolved in 2.5 litre of water such that its osmotic pressure is 0.75 atm at 27°C.
Determine the osmotic pressure of a solution prepared by dissolving 25 mg of K2SO4 in 2 liter of water at 25°C, assuming that it is completely dissociated.
Define the following term:
isotonic solution
Define the following term:
Hypotonic solution
What are hypertonic solutions?
Two solutions have different osmotic pressures. The solution of higher osmotic pressure is called ____________.
The average osmotic pressure of human blood is 7.8 bar at 37°C. What is the concentration of an aqueous NaCl solution that could be used in the blood stream?
Osmotic pressure of a solution is 0.0821 atm at a temperature of 300 K. The concentration in moles/litre will be:
The temperature at which 10% aqueous solution of (W/V) of glucose will show the osmotic pressure of 16.4 atoms is: (R = 0.082 L atom K−1 mol−1)
In isotonic solutions:
(i) Solute and solvent both are same.
(ii) Osmotic pressure is same.
(iii) Solute and solvent may or may not be same.
(iv) Solute is always same solvent may be different.
Match the items given in Column I and Column II.
| Column I | Column II |
| (i) Saturated solution | (a) Solution having same osmotic pressure at a given temperature as that of given solution. |
| (ii) Binary solution | (b) A solution whose osmotic pressure is less than that of another. |
| (iii) Isotonic solution | (c) Solution with two components. |
| (iv) Hypotonic solution | (d) A solution which contains maximum amount of solute that can be dissolved in a given amount of solvent at a given temperature. |
| (v) Solid solution | (e) A solution whose osmotic pressure is more than that of another. |
| (vi) Hypertonic solution | (f) A solution in solid phase. |
Which of the following colligative property can provide molar mass of proteins (or polymers or colloids) with greatest precision?
Which one of the following is a colligative property?
How will you determine molar mass of solute from osmotic pressure?
The 'X' g nonvolatile solute having molar mass 196 g mol-1 is dissolved in 3 dm³ water. Calculate the value of 'X' if resulting solution has osmotic pressure 0.8 atm at 300 К.
(R = 0.0821dm³ atm K-1 mol-1)
Calculate the osmotic pressure of 0.2 M aqueous solution of nonelectrolyte at 300 K.
[R = 0.082 atm dm3 mol−1K−1]
