Advertisements
Advertisements
प्रश्न
Calculate the hydrostatic pressure exerted by water at the bottom of a beaker. Take the depth of water as 40 cm, the density of water 1000 kgm−3 and g = 9.8 ms−2.
Advertisements
उत्तर
Pressure at the bottom of beaker = P =?
Height (or depth) of water in beaker = h = 40 cm
h= 0.4 m
Density of water = ρ
= 1000 kgm−3 Acceleration due to gravity = g = 9.8 ms−2
P = hρg
P = 0.4 × 1000 × 9.8
= 3920 Pa
APPEARS IN
संबंधित प्रश्न
What is the other name of buoyant force ?
The density of brass is 8.4 g cm-3. What do you mean by this statement?
Differentiate between thrust and pressure.
The pressure P1 at the top of a dam and P2 at a depth h form the top inside water (density p) are related as :
A body experiences an upthrust F1 in river water and F2 in sea water when dipped up to the same level. Which is more, F1 or F2? Give reason.
It is easier to lift a heavy stone under water than in air. Explain.
The base of the cylindrical vessel measures 300 cm2. Water is poured into it up to a depth of 6 cm. Calculate the pressure of water on the base in the vessel.
Select the correct option:
The phenomenon due to which a solid experiences upward force when immersed in water is called:
Is pressure a vector quantity?
If the buoyant force is less, the object will float.
