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प्रश्न
Calculate the hydrostatic pressure exerted by water at the bottom of a beaker. Take the depth of water as 40 cm, the density of water 1000 kgm−3 and g = 9.8 ms−2.
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उत्तर
Pressure at the bottom of beaker = P =?
Height (or depth) of water in beaker = h = 40 cm
h= 0.4 m
Density of water = ρ
= 1000 kgm−3 Acceleration due to gravity = g = 9.8 ms−2
P = hρg
P = 0.4 × 1000 × 9.8
= 3920 Pa
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