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प्रश्न
Calculate the energy radiated in one minute by a blackbody of surface area 100 cm2 when it is maintained at 227°C. (Given: σ = 5.67 × 10−8 W/m2.K4)
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उत्तर
Data:
t = one minute = 60 s,
A = 100 cm2
= 100 × 10−4 m2
= 10−2 m2,
T = 273 + 227
= 500 K,
σ = 5.67 × 10−8 W/m2 . K4
The energy radiated, Q = σAT4t
= (5.67 × 10−8)(10−2)(500)4(60) J
= (5.67)(625)(60)(10−2) J
= 2126 J
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