Advertisements
Advertisements
प्रश्न
Calculate the change in g value in your district of Tamil nadu. (Hint: Get the latitude of your district of Tamil nadu from Google). What is the difference in g values at Chennai and Kanyakumari?
Advertisements
उत्तर
Variation of ‘g’ value in the latitude to Chennai
`"g’"_"Chennai" = "g" - ω^2"R" cos^2λ`
Here `ω^2"R" = ((2π)/"T")^2 xx "R"`
Period of revolution (T) = 1 day = 86400 sec
Radius of the Earth (R) = 6400 × 103 m
Latitude of Chennai (λ) = 13° = 0.2268 rad
`"g’"_"Chennai" = 9.8 - [((2 xx 3.14)/86400)^2 xx 6400 xx 10^3] xx (cos 0.2268)^2`
= `9.8 - [(3.4 xx 10^-2) xx (0.9744)^2]`
= 9.8 − [0.034 × 0.9494]
= 9.8 − 0.0323
`"g’"_"Chennai"` = 9.7677 ms−2
Variation of ‘g’ value in the latitude of Kanyakumari
`"λ’"_"Kanyakumari"` = 8°35’ = 0.1457 red
`"g’"_"Kanyakumari" = 9.8 - [3.4 xx 10^-2 xx (cos 0.1457)^2]`
= 9.8 − 0.0333
`"g’"_"Kanyakumari"` = 9.7667 ms−2
The difference of ‘g’ value Δg = `"g’"_"Chennai" - "g’"_"Kanyakumari"`
= 9.7677 − 9.7667
Δg = 0.001 ms−2
APPEARS IN
संबंधित प्रश्न
Assuming the earth to be a sphere of uniform mass density, how much would a body weigh half way down to the centre of the earth if it weighed 250 N on the surface?
The acceleration of the moon just before it strikes the earth in the previous question is
Suppose, the acceleration due to gravity at the earth's surface is 10 m s−2 and at the surface of Mars it is 4⋅0 m s−2. A 60 kg passenger goes from the earth to the Mars in a spaceship moving with a constant velocity. Neglect all other objects in the sky. Which part of the following figure best represents the weight (net gravitational force) of the passenger as a function of time?

Find the acceleration due to gravity in a mine of depth 640 m if the value at the surface is 9.800 m s−2. The radius of the earth is 6400 km.
A particle is fired vertically upward from earth's surface and it goes up to a maximum height of 6400 km. Find the initial speed of particle.
Explain the variation of g with depth from the Earth’s surface.
Suppose we go 200 km above and below the surface of the Earth, what are the g values at these two points? In which case, is the value of g small?
If both the mass and the radius of the earth decrease by 1%, then the value of acceleration due to gravity will
A pebble is thrown vertically upwards from the bridge with an initial velocity of 4.9 m/s. It strikes the water after 2 s. If acceleration due to gravity is 9.8 m/s2. The height of the bridge and velocity with which the pebble strikes the water will respectively be ______.
The percentage decrease in the weight of a rocket, when taken to a height of 32 km above the surface of the earth will, be ______.
(Radius of earth = 6400 km)
