Question

Calculate the (a) velocity ratio (b) mechanical advantage (c) % age efficiency of a machine which overcomes a resistance of 800 N through a distance of 0.12 m, when an effort of 160 N acts through a distance of 0.72 m.

Answer 1

\[ \text{(a) Velocity ratio} = \frac{\text{Distance through which the effort moves}}{\text{Distance through which the load moves}} = \frac{0.72\ \text{m}}{0.12\ \text{m}} = 6 \]

\[ \text{(b) Mech. Adv.} = \frac{\text{Load}}{\text{Effort}} = \frac{800\ \text{N}}{160\ \text{N}} = 5 \]

\[ \text{(c) \% age efficiency} = \frac{\text{MA}}{\text{VR}} \times 100 = \frac{5}{6} \times 100 = 83.33\% \]