Question

 

Calculate the energy in fusion reaction:

`""_1^2H+_1^2H->_2^3He+n`, where BE of `""_1^2H`23He=7.73MeV" data-mce-style="position: relative;">=2.2323He=7.73MeV MeV and of `""_2^3He=7.73 MeV`

 

Answer 1

 

Given:
Binding energy of `""_1^2H`" data-mce-style="position: relative;" data-mce-tabindex="0"> E_{1 =  2.23 MeV}

_{Binding energy of}  `""_2^3H`E_{2= 7.73 MeV}

_{Energy in the fusion reaction is given by}

∆E=E₂−2E₁=7.73 − (2×2.23)=3.27 MeV