Question

Calcium chloride when dissolved in water dissociates into its ions according to the following equation.

\[\ce{CaCl2} (aq) → {Ca^{2+} (aq) + 2{Cl}- (aq)}\]

Calculate the number of ions obtained from CaCl₂ when 222 g of it is dissolved in water.

Answer 1

\[\ce{CaCl2} → Ca^{2+} + 2Cl^-\]

111 g (1 moles) → 1 moles + 2 moles

222 g (2 moles) → 2 moles + 4 moles

Total number of ions given by 2 moles of CaCl₂ = 6

Number of ions = Number of moles of ions × N_A

= 6 × 6.022 × 10²³

= 3.6132 × 10²⁴ ions