Question

By selling two transistors for Rs. 600 each, a shopkeeper gains 20 percent on one transistor and loses 20 percent on the other. Find :

1. C.P. of each transistor.
2. total C.P. and total S.P. of both the transistors.
3. profit or loss percent on the whole.

Answer 1

S.P. of first transistor = Rs. 600

Gain = 20%

(i) ∴ C.P. = `("S.P." xx 100)/(100 + "gain %")`

`= (600 xx 100)/(100 + 20)`

`= (600 xx 100)/120 = "Rs." 500`

S.P. of the second transistor = Rs. 600

Loss = 20%

∴ C.P. of the second transistor

`= ("S.P." xx 100)/(100 - "loss" %)`

`= (600 xx 100)/(100 - 20)`

`= "Rs." (600 xx 100)/80` = Rs. 750

∴ C.P. of the two transistors are Rs. 500 and Rs. 750

(ii) Total C.P. of both the transistors

= Rs. 500 + Rs. 750 = Rs. 1250

and total S.P. of both the transistors

= Rs. 600 + Rs. 600 = Rs. 1200

(iii) Total loss = C.P. - S.P.

= 1250 - 1200 = Rs. 50

∴ loss % =`("loss" xx 100)/"C.P."`

`= (50 xx 100)/1250 = 4%`