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प्रश्न
By actual division, show that x2 – 3 is a factor of` 2x^4 + 3x^3 – 2x^2 – 9x – 12.`
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उत्तर
Let f(x) = `2x^4 + 3x^3 – 2x^2 – 9x – 12` and g(x) as x^2 – 3
2x^2 + 3x + 4
Quotient q(x) = `2x^2 + 3x + 4`
Remainder r(x) = 0
Since, the remainder is 0.
Hence, x2 – 3 is a factor of `2x^4 + 3x^3 – 2x^2 – 9x – 12 `
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