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सी.आई.एस.सी.ई.आईसीएसई ICSE Class 8

Balance the Following Equation: \\Ce{Pb3o4 + Hcl->Pbcl2 + H2o + Cl2}\

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प्रश्न

Balance the following equation:

\[\ce{Pb3O4 + HCl->PbCl2 + H2O + Cl2}\]

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उत्तर

\[\ce{Pb3O4 + HCl->PbCl2 + H2O + Cl2}\]
There are 4 atoms of oxygen in Pb3O4 so make H atoms 8 in HCl.
\[\ce{Pb3O4 + 8HCl->PbCl2 + H2O + Cl2}\]
Multiply PbCl2 by 3 to make Pb atoms equal and H2O by 4.
\[\ce{Pb3O4 + 8HCl->3PbCl2 + 4H2O + Cl2}\]

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अध्याय 5: Language of Chemistry - Exercises

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