Advertisements
Advertisements
प्रश्न
Avneet buys 9 square paving slabs, each with a side of `1/2` m. He lays them in the form of a square.

- What is the perimeter of his arrangement [Fig (i)]?
- Shari does not like his arrangement. She gets him to lay them out like a cross. What is the perimeter of her arrangement [(Fig (ii)]?
- Which has greater perimeter?
- Avneet wonders if there is a way of getting an even greater perimeter. Can you find a way of doing this? (The paving slabs must meet along complete edges i.e. they cannot be broken.)
Advertisements
उत्तर
- Side of square = 3 × side
= `3 xx 1/2`
= `3/2`m
Perimeter of Square = `4 xx 3/2`
= 2 × 3
= 6 m - Perimeter = 0.5 + 1 + 1 + 0.5 + 1 + 1 + 0.5 + 1 + 1 + 0.5 + 1 + 1
= 10 m - The arrangement in the form of a cross has a greater perimeter.
- Perimeters greater than 10 m cannot be determined.
संबंधित प्रश्न
The diagonal of a square is 12 cm long; find its area and length of one side.
A path of uniform width, 3 m, runs around the outside of a square field of side 21 m. Find the area of the path.
Find the perimeter of the following figure

A square shaped park ABCD of side 100 m has two equal rectangular flower beds each of size 10 m × 5 m (Figure). Length of the boundary of the remaining park is ______.

Tahir measured the distance around a square field as 200 rods (lathi). Later he found that the length of this rod was 140 cm. Find the side of this field in metres.
Parmindar walks around a square park once and covers 800 m. What will be the area of this park?
The perimeter of a square garden is 48 m. A small flower bed covers 18 sq m area inside this garden. What is the area of the garden that is not covered by the flower bed? What fractional part of the garden is covered by flower bed? Find the ratio of the area covered by the flower bed and the remaining area.
Sweety runs around a square park of side 75 m. Bulbul runs around a rectangular garden with a length of 60 m and a breadth of 45 m. Who covers less distance?
In the following figure, perimeter of (ii) is the same as (i).
![]() |
![]() |
| (i) | (ii) |
Two figures can have the same area but different perimeters.


