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प्रश्न
Assign oxidation numbers to the underlined element in the following species:
NaH2PO4
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उत्तर
Let the oxidation number of P be x.
We know that,
Oxidation number of Na = +1
Oxidation number of H = +1
Oxidation number of O = - 2
⇒
| +1 | +1 | x | -2 |
| Na | H2 | P | O4 |
Then, we have
1(+1) + 2(+1) + 1(x) + 4(-2) = 0
⇒ 1 + 2 + x - 8 = 0
⇒ x = + 5
Hence, the oxidation number of P is + 5.
संबंधित प्रश्न
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Match Column I with Column II for the oxidation states of the central atoms.
| Column I | Column II |
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| (ii) \[\ce{MnO^{-}4}\] | (b) + 4 |
| (iii) \[\ce{VO^{-}3}\] | (c) + 5 |
| (iv) \[\ce{FeF^{3-}6}\] | (d) + 6 |
| (e) + 7 |
Match Column I with Column II for the oxidation states of the central atoms.
| Column I | Column II | |
| (i) | Ions having positive charge | (a) +7 |
| (ii) | The sum of oxidation number of all atoms in a neutral molecule |
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| (iv) | Oxidation number of fluorine in \[\ce{NaF}\] | (d) 0 |
| (v) | Ions having negative charge | (e) Cation |
| (f) Anion |
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