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Assertion (A): The value of ((\sin \theta+\cos \theta)) is always greater than 1. Reason (R): For (0^{\circ} \leq \theta \leq 90^{\circ}), the value of (\sin \theta) varies from 0 to 1

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प्रश्न

Assertion (A): The value of \((\sin \theta+\cos \theta)\) is always greater than 1.

Reason (R): For \(0^{\circ} \leq \theta \leq 90^{\circ}\), the value of \(\sin \theta\) varies from 0 to 1 and the value of \(\cos \theta\) varies from 1 to 0.

विकल्प

  • Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).

  • Both Assertion (A) and Reason (R) are true but Reason (R) is not a correct explanation of Assertion (А).

  • Assertion (A) is true and Reason (R) is false.

  • Assertion (A) is false and Reason (R) is true.

MCQ
अभिकथन और तर्क
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उत्तर

Assertion (A) is false and Reason (R) is true.

Explanation:

Step 1 – Assertion: A is false. At \(\theta=0^{\circ}\), \(\sin\theta+\cos\theta=0+1=1\), so the sum is not always greater than 1.

Step 2 – Reason: R is true. Over the stated interval, sine increases from 0 to 1 while cosine decreases from 1 to 0.

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अध्याय 20: Additional Questions - Trigonometry [पृष्ठ १०२४]

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आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 20 Additional Questions
Trigonometry | Q 7. | पृष्ठ १०२४
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