हिंदी

Assertion (A): The diameter of a sphere, whose surface area is $$616\ \mathrm{cm}^{2}$$, is 7 cm. Reason (R): The surface area of a sphere of radius $$r$$ is $$4\pi r^{2}$$.

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प्रश्न

Assertion (A): The diameter of a sphere, whose surface area is $$616\ \mathrm{cm}^{2}$$, is 7 cm.

Reason (R): The surface area of a sphere of radius $$r$$ is $$4\pi r^{2}$$.

विकल्प

  • Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).

  • Both Assertion (A) and Reason (R) are true but Reason (R) is not a correct explanation of Assertion (A).

  • Assertion (A) is true and Reason (R) is false.

  • Assertion (A) is false and Reason (R) is true.

MCQ
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उत्तर

Assertion (A) is false and Reason (R) is true.

Explanation:

Step 1 – Assertion: A is false. Using the given surface area and the sphere formula: $$4\pi r^{2} = 616$$ $$r^{2} = 49\ \mathrm{cm}^{2}, r = 7\ \mathrm{cm}$$ $$\text{Diameter} = 2r = 14\ \mathrm{cm}$$

Step 2 – Reason: R is true. The surface area of a sphere of radius $$r$$ is $$4\pi r^{2}$$.

Therefore, the correct option is: Assertion (A) is false and Reason (R) is true.

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अध्याय 20: Additional Questions - Volume and Surface Areas of Solids [पृष्ठ १०४६]

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आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 20 Additional Questions
Volume and Surface Areas of Solids | Q 1. | पृष्ठ १०४६
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