हिंदी

Assertion (A): The 50th term from the end of the G.P. $$4, 6, 9, \frac{27}{2}, .... \frac{6561}{64}$$ is $$\frac{27}{2}$$. Reason (R): nth term from the end of a G.P. is given by

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प्रश्न

Assertion (A): The 50th term from the end of the G.P. $$4, 6, 9, \frac{27}{2}, .... \frac{6561}{64}$$ is $$\frac{27}{2}$$. 

Reason (R): nth term from the end of a G.P. is given by $$\frac{l}{r^{n - 1}}$$.

विकल्प

  • Both A and R are true, and R is the correct explanation of A.

  • Both A and R are true, but R is not the correct explanation of A.

  • A is true, but R is false.

  • A is false, but R is true.

MCQ
अभिकथन और तर्क
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उत्तर

A is false, but R is true.

Explanation:

Reason R is true: the nth term from the end of a G.P. is $$\frac{l}{r^{n - 1}}$$. However, the given G.P. has $$a = 4$$, $$r = \frac{3}{2}$$ and $$l = \frac{6561}{64}$$, so it has only 9 terms; a 50th term from the end does not exist, making assertion A false.

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अध्याय 11: Geometric Progression - COMPETENCY-FOCUSED QUESTIONS [पृष्ठ १८३]

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आर.एस. अग्रवाल Mathematics [English] Class 10 ICSE
अध्याय 11 Geometric Progression
COMPETENCY-FOCUSED QUESTIONS | Q 2. | पृष्ठ १८३
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