हिंदी

Assertion (A) If the median and mode of a frequency distribution are 150 and154 respectively, then its mean is 148. Reason (R) Mean, median and mode of a frequency distribution are related as:

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प्रश्न

Assertion (A) Reason (R)
If the median and mode of a
frequency distribution are 150 and
154 respectively, then its mean is 148.
Mean, median and mode of a
frequency distribution are related as:
mode = 3 median – 2 mean.

विकल्प

  • Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).

  • Both Assertion (A) and Reason (R) are true but Reason (R) is not a correct explanation of Assertion (A).

  • Assertion (A) is true and Reason (R) is false.

  • Assertion (A) is false and Reason (R) is true.

MCQ
अभिकथन और तर्क
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उत्तर

Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).

Explanation:

Reason (R) is clearly true.

Using the relation given in Reason (R), we have

2 mean = (3 median) – (mode)

= (3 × 150) – (154) 

= 450 – 154

= 296

∴ Mean = 148, which is true.

Thus, Assertion (A) and Reason (R) are both true and Reason (R) is the correct explanation of Assertion (A).

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अध्याय 18: Mean, Median, Mode of Grouped Data, Cumulative Frequency Graph and Ogive - MULTIPLE-CHOICE QUESTIONS (MCQ) [पृष्ठ ९०४]

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आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 18 Mean, Median, Mode of Grouped Data, Cumulative Frequency Graph and Ogive
MULTIPLE-CHOICE QUESTIONS (MCQ) | Q 30. | पृष्ठ ९०४
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