हिंदी

Assertion (A): If A = (2⁢𝑥, 𝑦), B⁡(𝑥, 2⁢𝑦) and AB = 5 unit, then 𝑥 + 𝑦 = 5. Reason (R): [\sqrt{(x - 2x)^2 + (2y - y)^2} = 5] [\Rightarrow x^2 + y^2 = 25]

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प्रश्न

Assertion (A): If A = (2⁢𝑥, 𝑦), B⁡(𝑥, 2⁢𝑦) and AB = 5 unit, then 𝑥 + 𝑦 = 5.

Reason (R): \[\sqrt{(x - 2x)^2 + (2y - y)^2} = 5\] \[\Rightarrow x^2 + y^2 = 25\]

विकल्प

  • A is true, R is false.

  • A is false, R is true.

  • Both A and R are true and R is the correct reason for A.

  • Both A and R are true and R is the incorrect reason for A.

MCQ
अभिकथन और तर्क
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उत्तर

A is false, R is true.

Explanation:

  • Reason (R): Using the distance formula between A(2x, y) and B(x, 2y): \[\text{AB} = \sqrt{(x - 2x)^2 + (2y - y)^2} = \sqrt{(-x)^2 + y^2} = \sqrt{x^2 + y^2}\]
    Given AB = 5: \[\sqrt{x^2 + y^2} = 5 \implies x^2 + y^2 = 25\] Thus, Reason (R) is mathematically true.
  • Assertion (A): The equation \[x^2 + y^2 = 25\] represents a circle of radius 5 centred at the origin. It does NOT imply x + y = 5. For example, if x = -5, y = 0, then \[(-5)^2 + 0^2 = 25\], but \[x + y = -5 + 0 = -5 \neq 5\]. In algebra, \(\sqrt{x^2 + y^2} \neq x + y\). Hence, Assertion (A) is false.
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अध्याय 25: Distance Formula - TEST YOURSELF [पृष्ठ ३७४]

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सेलिना Concise Mathematics [English] Class 9 ICSE
अध्याय 25 Distance Formula
TEST YOURSELF | Q 1. (g) | पृष्ठ ३७४
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