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Assertion (A): If –5 is a root of $$2x^{2} + 2px - 15 = 0$$ and the equation $$p(x^{2} + x) + k = 0$$ has equal roots then $$k=\frac{7}{8}$$. Reason (R): The equation $$ax^{2} + bx + c = 0,\ a\neq 0$$

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प्रश्न

Assertion (A): If –5 is a root of $$2x^{2}+2px-15=0$$ and the equation $$p(x^{2}+x)+k=0$$ has equal roots then $$k=\frac{7}{8}$$.

Reason (R): The equation $$ax^{2}+bx+c=0,\ a\neq 0$$ has equal roots, if $$(b^{2}-4ac)=0$$.

विकल्प

  • Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).

  • Both Assertion (A) and Reason (R) are true but Reason (R) is not a correct explanation of Assertion (A).

  • Assertion (A) is true and Reason (R) is false.

  • Assertion (A) is false and Reason (R) is true.

MCQ
अभिकथन और तर्क
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उत्तर

Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).

Explanation:

Step 1 – Assertion: A is true. Substituting $$x=-5$$ into the first equation gives $$p=\frac{7}{2}.$$ The second equation is $$px^{2}+px+k=0.$$ For equal roots, $$p^{2}-4pk=0.$$ Since $$p=\frac{7}{2}\neq 0,$$ this gives $$k=\frac{p}{4}=\frac{7}{8}.$$

Step 2 – Reason: R is true. A quadratic equation has equal roots when its discriminant is zero.

Step 3 – Link: Applying this discriminant condition to the second equation gives the asserted value of $$k.$$

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अध्याय 20: Additional Questions - Quadratic Equations [पृष्ठ ९८६]

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आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 20 Additional Questions
Quadratic Equations | Q 8. | पृष्ठ ९८६
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