हिंदी

Assertion (A): For (0<\theta \leq 90^{\circ},(\operatorname{cosec} \theta-\cot \theta)) and ((\operatorname{cosec} \theta+\cot \theta)) are reciprocal of each other.

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प्रश्न

Assertion (A): For \(0<\theta \leq 90^{\circ},(\operatorname{cosec} \theta-\cot \theta)\) and \((\operatorname{cosec} \theta+\cot \theta)\) are reciprocal of each other.

Reason (R): \((\operatorname{cosec}^{2} \theta-\cot ^{2} \theta)=1\).

विकल्प

  • Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).

  • Both Assertion (A) and Reason (R) are true but Reason (R) is not a correct explanation of Assertion (А).

  • Assertion (A) is true and Reason (R) is false.

  • Assertion (A) is false and Reason (R) is true.

MCQ
अभिकथन और तर्क
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उत्तर

Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).

Explanation:

Step 1 – Assertion: A is true. Two quantities are reciprocals when their product is 1.

Step 2 – Reason: R is true. It gives the identity \(\operatorname{cosec}^{2} \theta-\cot ^{2} \theta=1\).

Step 3 – Link: \((\operatorname{cosec} \theta-\cot \theta\)\(\operatorname{cosec} \theta+\cot \theta)=\operatorname{cosec}^{2} \theta-\cot ^{2} \theta=1\). Thus, R correctly explains A.

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अध्याय 20: Additional Questions - Trigonometry [पृष्ठ १०२३]

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आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 20 Additional Questions
Trigonometry | Q 1. | पृष्ठ १०२३
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