हिंदी

Assertion (A): A top is of the shape of a cone mounted over a hemisphere of the same radius. If the radius of the hemisphere is 3.5 cm and the total height of the top is 15.5 cm

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प्रश्न

Assertion (A): A top is of the shape of a cone mounted over a hemisphere of the same radius. If the radius of the hemisphere is 3.5 cm and the total height of the top is 15.5 cm then the total surface area of the top is $$214.5\ \mathrm{cm}^{2}$$.

Reason (R): The total surface area of the top is the sum of the curved surface area of the hemisphere and the curved surface area of the cone.

विकल्प

  • Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).

  • Both Assertion (A) and Reason (R) are true but Reason (R) is not a correct explanation of Assertion (A).

  • Assertion (A) is true and Reason (R) is false.

  • Assertion (A) is false and Reason (R) is true.

MCQ
अभिकथन और तर्क
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उत्तर

Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).

Explanation:

Step 1 – Assertion: A is true. The cone’s height is $$15.5 - 3.5 = 12\ \mathrm{cm}$$ and its slant height is $$\sqrt{12^{2} + 3.5^{2}} = 12.5\ \mathrm{cm}$$. Thus: $$\text{Total surface area} = \pi rl + 2\pi r^{2}$$ $$= \frac{22}{7} \times 3.5 \times 12.5 + 2 \times \frac{22}{7} \times (3.5)^{2} = 214.5\ \mathrm{cm}^{2}$$

Step 2 – Reason: R is true. The joined circular faces are internal, so the exposed area is the sum of the cone’s and hemisphere’s curved surface areas.

Step 3 – Link: This is precisely the method used to calculate the total exposed surface area in A, so R correctly explains A.

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अध्याय 20: Additional Questions - Volume and Surface Areas of Solids [पृष्ठ १०४८]

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आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 20 Additional Questions
Volume and Surface Areas of Solids | Q 11. | पृष्ठ १०४८
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