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प्रश्न
Arrange the given rational numbers in descending order:
`3/-10, (-13)/30 "and" 8/-20`
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उत्तर
`3/-10, (-13)/30 "and" 8/-20`
`= (-3)/10, (-13)/30 "and" (- 8)/20`
`= (-3 xx 6)/(10 xx 6), (-13 xx 2)/(30 xx 2) "and" (-8 xx 3)/(20 xx 3)`
(∵ LCM of 10, 20 and 30 = 60)
`= (-18)/60, (-26)/60` and `(-24)/60`

Since, - 18 > - 24 > - 26
`therefore (- 18)/60 > (-24)/60 > (-26)/60`
`=> (-3)/10 > (-8)/20 > (-13)/30`
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संबंधित प्रश्न
Arrange the given rational numbers in descending order:
`5/8, 13/-16 "and" (-7)/12`
Fill in the blank:
`5/8` and `3/10` are on the ________ side of zero.
Add: `5/-12 "and" 1/12`
Evaluate: `-2 + 2/5 + (-2)/15`
Subtract:
`(- 6)/25 "from" (-8)/5`
Subtract: `0 "from" (-3)/8`
Evaluate: `((-8)/9) xx ((-3)/16)`
Multiply: `6 2/3 "and" (-3)/8`
By what rational number should we multiply `20/-9`, so that the product may be `(-5)/9`?
Evaluate: `7/-26 + 16/39`
