Question

Applying Dr. Morgans theorem to the expression ((x+y)'+z)', we get ______.

विकल्प

• (x + y)z

• (x' + y')z

• (x + y)z'

• (x' + y')z'

Answer 1

Applying Dr. Morgans theorem to the expression ((x+y)'+z)', we get (x + y)z'.

Explanation:

Let P = (x+y)'.

Then [(P+z)'=P'z'] would appear if the expression were [((x+y)'+z)').

Since [P'=((x+y)')'=x+y],

the result is [(x+y)z'].