Question

Answer the following:

Show that, `log ("a"^2/"bc") + log ("b"^2/"ca") + log ("c"^2/"ab")` = 0

Answer 1

L.H.S. = `log ("a"^2/"bc") + log ("b"^2/"ca") + log ("c"^2/"ab")` 

= `log ("a"^2/"bc" xx "b"^2/"ca" xx "c"^2/"ab")`

= `log(("a"^2"b"^2"c"^2)/("a"^2"b"^2"c"^2))`

= log 1

= 0

= R.H.S.