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Answer the following: Find the equation of the tangent to the hyperbola x225−y216 = 1 at P(30°) - Mathematics and Statistics

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प्रश्न

Answer the following:

Find the equation of the tangent to the hyperbola `x^2/25 − y^2/16` = 1 at P(30°)

योग
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उत्तर

The equation of the hyperbola is `x^2/25 − y^2/16` = 1

Comparing this with `x^2/"a"^2 - y^2/"b"^2` = 1, we get,

a2 = 25, b2 = 16

∴ a = 5, b = 4

The equation of the tangent to the hyperbola

`x^2/"a"^2 - y^2/"b"^2` = 1 at P(θ) is

`x/"a"sectheta - y/"b"tantheta` = 1

∴ the equation of the tangent to the given hyperbola at P (30°) is

`x/5sec30^circ - y/4tan30^circ` = 1

∴ `x/5(2/sqrt(3)) - y/4(1/sqrt(3))` = 1

∴ 8x – 5y = `20sqrt(3)`

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Conic Sections - Hyperbola
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Conic Sections - Miscellaneous Exercise 7 [पृष्ठ १७८]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 7 Conic Sections
Miscellaneous Exercise 7 | Q II. (23) (iii) | पृष्ठ १७८

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