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Answer the following: Find the equation of the hyperbola in the standard form if eccentricity is 32 and distance between foci is 12 - Mathematics and Statistics

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प्रश्न

Answer the following:

Find the equation of the hyperbola in the standard form if eccentricity is `3/2` and distance between foci is 12.

योग
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उत्तर

Let the required equation of hyperbola be `x^2/"a"^2 - y^2/"b"^2` = 1

Given, eccentricity (e) = `3/2`

Distance between foci = 2ae

Given, distance between foci = 12

∴ 2ae = 12

∴ `2"a"(3/2)` = 12

∴ 3a = 12

∴ a = `12/3` = 4

∴ a2 = 16

Now, b2 = a2(e2 – 1)

∴ b2 = `16[(3/2)^2 - 1]`

= `16(9/4 - 1)`

= `16(5/4)`

∴ b2 = 20

∴ The required equation of hyperbola is `x^2/16 - y^2/20` = 1.

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Conic Sections - Hyperbola
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Conic Sections - Miscellaneous Exercise 7 [पृष्ठ १७८]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 7 Conic Sections
Miscellaneous Exercise 7 | Q II. (22) (ii) | पृष्ठ १७८

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