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Answer the following : Find the equation of the circle concentric with x2 + y2 – 4x + 6y = 1 and having radius 4 units - Mathematics and Statistics

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प्रश्न

Answer the following :

Find the equation of the circle concentric with x2 + y2 – 4x + 6y = 1 and having radius 4 units

योग
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उत्तर

Given equation of circle is

x2 + y2 – 4x + 6y = 1

i.e., x2 + y2 – 4x + 6y – 1 = 0

Comparing this equation with

x2 + y2 + 2gx + 2fy + c = 0, we get

2g = –4, 2f = 6

∴ g = –2, f = 3

∴ Centre of the circle = (–g, –f) = (2, –3)

Given circle is concentric with the required circle.

∴ They have same centre.

∴ Centre of the required circle = (2, –3)

The equation of a circle with centre at (h, k) and radius r is

(x – h)2 + (y – k)2 = r2

Here, h = 2, k = –3 and r = 4

∴ the required equation of the circle is

(x – 2)2 + [y – (–3)]2 = 42

∴ (x – 2)2 + (y + 3)2 = 16

∴ x2 – 4x + 4 + y2 + 6y + 9 – 16 = 0

∴ x2 + y2 – 4x + 6y – 3 = 0.

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अध्याय 6: Circle - Miscellaneous Exercise 6 [पृष्ठ १३७]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 6 Circle
Miscellaneous Exercise 6 | Q II. (10) | पृष्ठ १३७

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