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Answer the following: Find f(x) if g(x) = x2 + x – 2 and (g ° f) (x) = 4x2 – 10x + 4

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प्रश्न

Answer the following:

Find f(x) if g(x) = x2 + x – 2 and (g ° f) (x) = 4x2 – 10x + 4

योग
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उत्तर

g(x) = x2 + x – 2 and (g ° f) (x) = 4x2 – 10x + 4

4x2 – 10x + 4 = g[f(x)] = [f(x)]2 + [f(x)] – 2

∵ deg(4x2 – 10x + 4) = 2

∴ deg [f(x)] = 1

Let f(x) = ax + b, a, b ∈ R

∴ 4x2 – 10x + 4 = (ax + b)2 + (ax + b) – 2

= a2x2 + 2abx + b2 + ax + b – 2

= a2x2 + (2ab + a)x + b2 + b – 2

Comparing the corresponding coefficients, we get

a2 = 4    ...(1)

2ab + a = – 10  ...(2)

b2 + b – 2 = 4   ...(3)

From (1), a = ± 2

If a = 2, from (2), 4b + 2 = – 10

∴ b = – 3

b = – 3 satisfies b2 + b – 2 = 4

∴ f(x) = 2x – 3 is one possibility

If a = – 2, from (2), – 4b – 2 = – 10

∴ b = 2

b = 2 satisfies (3)

∴ f(x) = – 2x + 2 is other possibility

∴ f(x) = 2x – 3 or f(x) = – 2x + 2

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अध्याय 6: Functions - Miscellaneous Exercise 6.2 [पृष्ठ १३२]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 6 Functions
Miscellaneous Exercise 6.2 | Q II. (43) (a) | पृष्ठ १३२

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