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An object was launched from a place P in constant speed to hit a target. At the 15th second, it was 1400 m from the target, and at the 18th second 800 m away. Find time taken to hit the target - Mathematics

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प्रश्न

An object was launched from a place P in constant speed to hit a target. At the 15th second, it was 1400 m from the target, and at the 18th second 800 m away. Find time taken to hit the target

योग
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उत्तर

Let us take the time T along the x-axis and the Distance D along the y-axis.

Given when time T = 15s, the distance D = 1400 m

The corresponding point is (15, 1400)

Also when time T = 18s, the distance D = 800 m.

The corresponding point is (18, 800)

Time taken to hit the Target:

When the target is reached D = 0

∴ (1) ⇒ T = `(1400 - 0)/200 + 15`

T = `1400/200 + 15`

T = 7 + 15

= 22 seconds

∴ The time taken to hit the target is 22 seconds

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Two Dimensional Analytical Geometry - Exercise 6.2 [पृष्ठ २६०]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 6 Two Dimensional Analytical Geometry
Exercise 6.2 | Q 6. (iii) | पृष्ठ २६०

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