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An Nacl Molecule is Bound Due to the Electric Force Between the Sodium and Chlorine Ions When One Electron of Sodium is Transferred to Chlorine. Taking Separation Between the Ions to Be 2.75 × 10−8 Cm - Physics

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प्रश्न

NaCl molecule is bound due to the electric force between the sodium and the chlorine ions when one electron of sodium is transferred to chlorine. Taking the separation between the ions to be 2.75 × 10−8 cm, find the force of attraction between them. State the assumptions (if any) that you have made. 

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उत्तर

Let the given separation between the ions, i.e. 2.75 × 10−8 cm, be the separation between the transferred electron and the sodium nucleus. 

Net charge on thechlorine ion, q1 = \[- 1 . 6 \times  {10}^{- 19}\] c

Net charge on the sodium ion, q2 = \[1 . 6 \times  {10}^{- 19}\] c

By Coulomb's Law, force,           

 
\[F = \frac{1}{4\pi \epsilon_0}\frac{q_1 q_2}{r^2}\]

\[= \frac{9 \times {10}^9 \times \left( 1 . 6 \times {10}^{- 19} \right)^2}{\left( 2 . 75 \times {10}^{- 10} \right)^2}\] 

\[ = 3 . 05 \times  {10}^{- 9}   N\]

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अध्याय 7: Electric Field and Potential - Exercises [पृष्ठ १२१]

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एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
अध्याय 7 Electric Field and Potential
Exercises | Q 13 | पृष्ठ १२१

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