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प्रश्न
An element X has a valency of 2. Write the simplest formula for oxide of the element.
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उत्तर
Valency of X = 2
Valency of Oxygen = 2
Formula for oxide of element X can be worked out by crossing the valencies of the constituent elements.
Therefore, formula for oxide of X is XO.
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An element X has a valency of 2. Write the simplest formula for bromide of the element.
Explain the formation of (i) sodium ion, and (ii) chloride ion, from their respective atoms giving the number of protons and number of electrons in each one of them. What is the reason for positive charge on a sodium ion and a negative charge on a chloride ion ?
The valencies (or charges) of some of the ions are given below :
| Ion | Valency (Charge) | Ion | Valency (Charge) |
| Sodium ion | 1+ | Bromide ion | 1– |
| Ammonium ion | 1+ | Hydroxide ion | 1– |
| Calcium ion | 2+ | Sulphate ion | 2– |
| Lead ion | 2+ | Phosphate ion | 3– |
Using this information, write down the formulae of the following compounds :
(i) Sodium phosphate
(ii) Ammonium sulphate
(iii) Calcium hydroxide
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Give example.
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State if the following element or radical is divalent?
Dichromate
Match the names of ions and radicals from 1 to 10 with their correct answer from A to Q.
| Column A | Column B |
| 1. Hypochlorite | A: Hg2+ |
| 2. Permanganate | B: \[\ce{MnO_4^1-}\] |
| 3. Plumbous | C: Sn4+ |
| 4. Zincate | D: Pb2+ |
| 5. Nitride | E: Sn2+ |
| 6. Mercuric | F: Pb4+ |
| 7. Stannic | G: \[\ce{SO_3^2-}\] |
| 8. Nitrite | H: N3- |
| 9. Sulphite | I: \[\ce{NO_2^1-}\] |
| 10. Dichromate | J: \[\ce{MnO_4^2-}\] |
| K: Hg1+ | |
| L: \[\ce{SO_4^2-}\] | |
| M: CIO1- | |
| N: \[\ce{ZnO_2^2-}\] | |
| O: \[\ce{Cr_2O_7^2-}\] | |
| P: \[\ce{CrO_4^2-}\] | |
| Q: \[\ce{ClO_3^1-}\] |
