Question

According to Ampere's Circuital Law, the line integral \[\oint\vec{B}\cdot d\vec{l}\] taken around any closed loop equals:

विकल्प

• \[\mu_0\] times the net steady current passing through the loop

• \[\mu_0\] times the net current divided by the loop's perimeter

• The net current enclosed divided by \[\mu_0\]

• Zero for every closed loop

Answer 1

The law states that \[\oint\vec{B}\cdot d\vec{l}=\mu_0 I\], where \[I\] is the net steady current passing through the loop. The result holds for any closed Amperian loop, not just circular ones.