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प्रश्न
`square`ABCD is a cyclic quadrilateral where side AB ≅ side BC, ∠ADC = 110°, AC is the diagonal, then:
- Draw the figure using given information
- Find measure of ∠ABC
- Find measure of ∠BAC
- Find measure of (arc ABC).
योग
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उत्तर
a.

b. m∠ADC + m∠ABC = 180° ...[Cyclic quadrilateral theorem]
∴ 110° + m∠ABC = 180°
∴ m∠ABC = 180° − 110°
∴ m∠ABC = 70°
c. ΔABC is an isosceles triangle. (AB = BC)
∴ m∠ABC = m∠BCA ...[Isosceles triangle theorem]
∴ m∠BAC + m∠ACB + m∠ABC = 180° ...[Angle sum property of a triangle]
∴ m∠BAC + m∠BAC + 70° = 180°
∴ 2m∠BAC = 180° − 70°
∴ 2m∠BAC = 110°
∴ m∠BAC = 55°
d. m∠ADC = `1/2` m(arc ABC) ...[Inscribed angle theorem]
∴ 110° = `1/2` m(arc ABC)
∴ m(arc ABC) = 220°
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