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प्रश्न
ABC is an isosceles triangle with AB = AC = 12 cm and BC = 8 cm. The area of the triangle is ______.
विकल्प
`32sqrt{2}" cm"^2`
`16sqrt{2}" cm"^2`
`8sqrt{2}" cm"^2`
`12sqrt{2}" cm"^2`
MCQ
रिक्त स्थान भरें
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उत्तर
ABC is an isosceles triangle with AB = AC = 12 cm and BC = 8 cm. The area of the triangle is `bbunderline(32sqrt{2}" cm"^2)`.
Explanation:
The height (altitude) AD to the base BC bisects it into segments of 4 cm.
Using Pythagoras’ theorem,
AD = `sqrt{12^2 - 4^2} = sqrt{128} = 8sqrt{2}" cm"`,
giving an area of `1/2 xx 8 xx 8sqrt{2} = 32sqrt{2}" cm"^2`.
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