Advertisements
Advertisements
प्रश्न
AB (= 10 unit) is diameter of a circle with centre at point P = (x, 0) and point B = (0, y). The relation between x and y is:

विकल्प
x + y = 10
x + y = 25
\(x^2+y^2=5\)
\(x^2+y^2=25\)
MCQ
Advertisements
उत्तर
\[\mathbf{x^2+y^2=25}\]
Explanation:
Since (AB) is a diameter, the radius is \[PB=\frac{10}{2}=5\text{ units}.\] Also, \[PB=\sqrt{(x-0)^2+(0-y)^2}=\sqrt{x^2+y^2}.\] Hence, \[x^2+y^2=25.\] Option (iv) is correct.
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
