Question

A vessel of 120 mL capacity contains a certain amount of gas at 35 °C and 1.2 bar pressure. The gas is transferred to another vessel of volume 180 mL at 35 °C. What would be its pressure?

Answer 1

Given,

Initial pressure, p₁ = 1.2 bar

Initial volume, V₁ = 120 mL

Final volume, V₂ = 180 mL

Since the temperature remains constant, the final pressure (p₂) can be calculated using Boyle’s law.

According to Boyle’s law,

`"p"_1"V"_1 = "p"_2"V"_2`

`"p"_2 = ("p"_1"V"_1)/"V"_2`

`= (1.2 xx 120)/180 "bar"`

`= 0.8 " bar"`

Therefore, the pressure would be 0.8 bar.